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3 years ago

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Given the parent functions f(x) = 5x − 1 and g(x) = 3x − 9, what is g(x) − f(x)?

1 answer:

MissTica3 years ago

5 0

F(x) = 5x − 1

and g(x) = 3x − 9

g(x) - f(x) = (3x − 9) - (5x − 1) ===> -2x-8

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Select the correct answer.

Eva8 [605]

Answer:

Equation C: 5/8x + 2..5 = 3/8x + 1.5 + 1/4x

Step-by-step explanation:

Let us go through each of the equations one by one.

Equation A: $2.3y+2+3.1y=4.3y+1.6+1.1y+0.4$

This simplifies to

$5.4y+2=5.4y+2$

which has infinitely many solutions.

Equation B: $32x+25-21x=10x$

this simplifies to

$x+25=0$

$x=-25$

which is exactly one solution.

Equation C: $\frac{5}{8} x+2.5=\frac{3}{8}x+1.5+\frac{1}{4} x$

this simplifies to

$\frac{5}{8} x+2.5=\frac{5}{8} +1.5$

$2.5=1.5$

There's no way this is going to be possible; this equation has no solutions.

Equation D: $\frac{1}{3} x+\frac{1}{7} x=\frac{3}{7} x$

this gives

$\frac{1}{3} =\frac{2}{7} y$

$y=\frac{7}{6}$

which is exactly one solution.

Thus we see that it is equation C that has no solutions.

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Zielflug [23.3K]

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Please help. Thank you in advance.

ivolga24 [154]

Answer:

The second choice is the same so it is the last one

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"13 less than two-thirds of a number"

Sindrei [870]

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Determine whether the following series converge or diverge

Mars2501 [29]

An alternating series $\sum\limits_n(-1)^na_n$ converges if $|(-1)^na_n|=|a_n|$ is monotonic and $a_n\to0$ as $n\to\infty$ . Here $a_n=\dfrac1{\ln(n+1)}$ .

Let $f(x)=\ln(x+1)$ . Then $f'(x)=\dfrac1{x+1}$ , which is positive for all $x>-1$ , so $\ln(x+1)$ is monotonically increasing for $x>-1$ . This would mean $\dfrac1{\ln(x+1)}$ must be a monotonically decreasing sequence over the same interval, and so must $a_n$ .

Because $a_n$ is monotonically increasing, but will still always be positive, it follows that $a_n\to0$ as $n\to\infty$ .

So, $\sum\limits_n(-1)^na_n$ converges.

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3 years ago