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jekas [21]
3 years ago
12

Given the parent functions f(x) = 5x − 1 and g(x) = 3x − 9, what is g(x) − f(x)?

Mathematics
1 answer:
MissTica3 years ago
5 0
F(x) = 5x − 1

and g(x) = 3x − 9


g(x) - f(x) = (3x − 9) - (5x − 1) ===> -2x-8
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Select the correct answer.
Eva8 [605]

Answer:

Equation C: 5/8x + 2..5 = 3/8x + 1.5 + 1/4x

Step-by-step explanation:

Let us go through each of the equations one by one.

Equation A: 2.3y+2+3.1y=4.3y+1.6+1.1y+0.4

This simplifies to

5.4y+2=5.4y+2

which has infinitely many solutions.

Equation B: 32x+25-21x=10x

this simplifies to

x+25=0

x=-25

which is exactly one solution.

Equation C: \frac{5}{8} x+2.5=\frac{3}{8}x+1.5+\frac{1}{4} x

this simplifies to

\frac{5}{8} x+2.5=\frac{5}{8} +1.5

2.5=1.5

There's no way this is going to be possible; this equation has no solutions.

Equation D: \frac{1}{3} x+\frac{1}{7} x=\frac{3}{7} x

this gives

\frac{1}{3} =\frac{2}{7} y

y=\frac{7}{6}

which is exactly one solution.

Thus we see that it is equation C that has no solutions.

3 0
4 years ago
I need help in sovling this probelm. simplify (2xyz)^0
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ivolga24 [154]

Answer:

The second choice is the same so it is the last one

7 0
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An alternating series \sum\limits_n(-1)^na_n converges if |(-1)^na_n|=|a_n| is monotonic and a_n\to0 as n\to\infty. Here a_n=\dfrac1{\ln(n+1)}.

Let f(x)=\ln(x+1). Then f'(x)=\dfrac1{x+1}, which is positive for all x>-1, so \ln(x+1) is monotonically increasing for x>-1. This would mean \dfrac1{\ln(x+1)} must be a monotonically decreasing sequence over the same interval, and so must a_n.

Because a_n is monotonically increasing, but will still always be positive, it follows that a_n\to0 as n\to\infty.

So, \sum\limits_n(-1)^na_n converges.
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3 years ago
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