3 years ago

Find the solutions to x^2=12

1 answer:

7 0

Answer:

x=2 $\sqrt{3}$

Step-by-step explanation:

$x^{2} =12\\x=\sqrt{12} \\x=\sqrt{4 times 3} \\x=2\sqrt{3}$

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Answer:

$log_{b} b^{n}$ = n.

Step-by-step explanation:

Given : $log_{b} b^{n}$ , b is any positive number not equal to 1 and n is any number.

To find : Evaluate the expression $log_{b} b^{n}$ .

Formula used : $log_{b} x^{y}$ . = y ∙ $log_{b}$ (x) and

$log_{b}(b) = 1.Solution : We have [tex]log_{b} b^{n}$ .

By logarithm rule : $log_{b} x^{y}$ . = y ∙ $log_{b}$ (x).

Then $log_{b} b^{n}$ = n∙ $log_{b}$ (b).

By logarithm rule : $log_{b}(b) = 1.Now, n∙ [tex]log_{b}$ (b) = n.

Therefore, $log_{b} b^{n}$ = n.

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