Answer:
Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.
Step-by-step explanation:
we have
Hiroshi's work

Remember that
a negative number is just a positive number multiplied by -1
and (-1)(-1)=+1
so
Correct work





therefore
Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.
Answer:
-23/4
Step-by-step explanation:




Answer:
Tomas added 6 to both sides of the equation instead of subtracting 6.
Step-by-step explanation:
Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation 2x + 6y = 12 to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy.
Given:
2x + 6y = 12
where
x = number of pounds of granola y = number of pounds of walnuts
The correct solution to the problem
x = 3 pounds
2x + 6y = 12
2(3) + 6y = 12
6 + 6y = 12
Subtract 6 from both sides
6 + 6y - 6 = 12 - 6
6y = 6
Divide both sides by 6
y = 6/6
= 1
y = 1 pound
Tomas added 6 to both sides of the equation instead of subtracting 6.
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.