The answer of this question is 6/19. I hope this helps
Answer:
338 different options we will have to choose from.
Step-by-step explanation:
Number of base drinks = 13
Numbers of flavors = 26
If we can select 1 base and 1 flavor.
For every base drink we have 26 flavors.
Then for each 13 base drinks we will have 26 flavors.
So, number of options if we have If we select 1 base and 1 flavor:

338 different options we will have to choose from.
This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
x=[-b+/-sqrt(b^2-4ac)]/(2a)
from our equation, a=2,b=-12 and c=20
x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
x=[12+/-sqrt(144-160]/4
x=[12+/-sqrt(-16)]/4
x=[12+/-4i]/4
x=[3+\-i]
the answer is A] 3+/-i
Answer:
1.28
2. -3.5
3.-10.5
Step-by-step explanation:
1.-0.0035 · 12000+70= 28
2. -0.0035 ·21000+70=-3.5
3. -0.0035 ·23000+70=-10.5
I hope this helps
Answer:
I and II.
Step-by-step explanation:
Dot plots are charts that<em> represent data points on a simple scale using filled circles</em>. Stemplots allow <em>plotting data by dividing it into stems (largest digit) and leaves (smallest digits)</em>. Both dot plots and stemplots are like histograms since they allow to compare data relating to only one variable, and are used for continuous, quantitive data, highlighting gaps, clusters, and outliers.
Histograms <em>use bars to represents amounts, with no space between the bars and </em>the height of the bars is proportional to the frequency or relative frequency of the represented amount. <u>We refer to the relative frequency of a case when this frequency is divided by the sum of all frequencies of the cases</u>. The proportionality between the height of the bar and the frequency is right when the width (interval) of the bar is the same for everyone, on the contrary, the area of the bar would be proportional to the frequency of cases.
Therefore, of all the above, the correct statements are I and II. Statement III is incorrect because relative <em>heights </em>are proportional to relative <em>frequencies</em>.
I hope it helps you!