There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)
1.) 27/x^3
2.) a^8/b^12
3.) 7^36/81 OR 13,841,287,201/81
4.) 256m^20/n^4
5.) x^6y^6
6.) 64k^4/k^6
7.) 1,000a^9b^6/a^6b^9
8.) 81x^21/625
9.) 2304/x^16y^12
10.) x^7z^14/y^21
11.) 7,776k^5
12.) x^24y^24/4,096
Hope it’s all helped
I really hope this helps. I’m sure the answer is c:)
Answer:b
Step-by-step explanation:
(×+1)(×-1)
---------------
(×+1)(×+7)
=cancel (×+1) both the numerator and denominator then you are left with
(×-1)
-------
(×+7)
=(×-1)/(×+7)
Answer:
6
Step-by-step explanation:
Find the predicted y value when x=1:

Find the residual:

Because our residual is positive, this is an indicator that our predicted y value is too low.
Answer:
x = -11/5 and y = 24/5
Step-by-step explanation:
Use elimination.
First, we need to multiply so that at least one variable can cancel out.
We can multiply the top equation by 2.
So we get
4x + 6y = 20
Then, we can use elimination.
The x's cancel out.
So we get 5y = 24
Or y = 24/5
Then, we can plug in this y value back into the first equation to find x.
2x + 3(24/5) = 10
2x + 72/5 = 50/5
2x = -22/5
x = -11/5
So x = -11/5 and y = 24/5