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anastassius [24]
4 years ago
13

Numerical value of cosh(ln5)

Mathematics
1 answer:
strojnjashka [21]4 years ago
6 0
\cosh x=\dfrac{e^x+e^{-x}}2

So

\cosh(\ln 5)=\dfrac{e^{\ln5}+e^{-\ln5}}2=\dfrac{5+\frac15}2=\dfrac{13}5
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If x =26 and y=2 what is my constant of proportionality?Reduce answer
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Answer:

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Step-by-step explanation:

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422

Step-by-step explanation:

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3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
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Answer:

The answer is

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Step-by-step explanation:

Remember that Taylor says that

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For this case

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5 0
3 years ago
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