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anastassius [24]
3 years ago
13

Numerical value of cosh(ln5)

Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0
\cosh x=\dfrac{e^x+e^{-x}}2

So

\cosh(\ln 5)=\dfrac{e^{\ln5}+e^{-\ln5}}2=\dfrac{5+\frac15}2=\dfrac{13}5
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