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galina1969 [7]
3 years ago
12

Jon ran around the track that was 1/8 of a mile. He ran around the track 24 times for a total of how many miles?

Mathematics
1 answer:
valina [46]3 years ago
6 0
3 cause 1/8 times 24/1 = 24/8 divided =3 
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Is y^2=4x-7 a linear
Vinvika [58]

Answer: it's a linear equation

Step-by-step explanation:

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How do you write an equation of a line given y-intercept -8 and slope 3/4
Lostsunrise [7]

Answer:

y = \frac{3}{4} x-8

Step-by-step explanation:

You can us the equation y = m x + c to answer this question.

In ,

y = m x + c

m = slope

c = y - intercept

So, they have already given in the question that,

m = 3/4

c = (-8)

Therefore, you can simply put 3/4 and (-8) instead of m and c respectively like this.

y = m x + c

y = 3/4x - 8

Hope this helps you.

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3 years ago
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Heeeeeelp! I’m literally so behind
olchik [2.2K]

Answer:

That would be 9 my good sir ( or ma'am )

Step-by-step explanation:

basicly round the 61 so that there would not be a remainder and divide 54 by 6 you will get 9, so therefore the same case is for 540 by 60.

Have a nice day

7 0
3 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
System of equations<br><br>y=1/2x +5<br>y=3x -5​
Art [367]

Answer: 4

Step-by-step explanation:

Set them equal to each other since they're both equal to y

3x-5=.5x +5

add 5 to both sides

3x=.5x+10

subtract .5x from both sides

2.5x=10

divide both sides by 2.5

x= 4

5 0
3 years ago
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