**15 Points!! What is 2 1/2 x 1 1/2, 5.4 x 2 3/4, and 3.1 x 2/7?

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

Please help me if you know it

tino4ka555 [31]

Answer:

c is right answer bro ok ....

3 0

2 years ago

How do I find X in this problem

pogonyaev

You know that BC is congruent to x so you need to solve for x using the ratio:
$\frac{12}{24}=\frac{x}{BC}$

So then we need to find BC.

We know:
$A=\frac{base \times height}{2}$
$28=\frac{BC \times 7}{2}$
Therefore BC =8

Then:
$\frac{12}{24}=\frac{x}{8}$
$x=8 \times \frac{12}{24} = 4$

4 0

3 years ago

En una tienda de ropa vas a comprarte una pantalones que están de 150 a 90 euros y una camiseta de 40 a 24 ¿ tienen el mismo por

uranmaximum [27]

Respuesta:

Sí, tienen el mismo descuento del 40%

Explicación paso a paso:

Dado :

PANTALÓN :

Precio inicial = 150

Precio con descuento = 90

Porcentaje de descuento en el precio:

(150 - 90) / 150 * 100%

60/150 * 100%

0,4 * 100

= 40%

CAMISA:

Precio inicial = 40

Precio con descuento = 24

Porcentaje de descuento en el precio:

(40-24) / 150 * 100%

16/40 * 100%

0,4 * 100

= 40%

Sí, tienen el mismo descuento del 40%

8 0

3 years ago

Estimate the length of the segment

Lapatulllka [165]

I’m not sure if it’s correct but I think you have to find the slope in order to get your answer

7 0

2 years ago

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