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Yuliya22 [10]
3 years ago
15

The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of len

gth fraction 1 over 3 unit and width fraction 1 over 2 unit?
fraction 2 over 5 unit
fraction 4 over 5 unit
fraction 1 and 1 over 3 units
fraction 1 and 2 over 3 units
Mathematics
2 answers:
likoan [24]3 years ago
7 0

Answer:

The answer is D.) Fraction 1 2/3.

I recently did this test on FLVS

Hope this helped!

Have a wonderful Wednesday!

~Lola

Allisa [31]3 years ago
4 0
First you plug in the data to the formula. So it will be 2(1/3+1/2). You then want to add the fractions together but must first find the common denominator which will be 6. So it is 2(2/6+3/6). The fractions then add up to be 5/6. So all you have to do is multiply it by 2 to get 5/3 which simplifies to 1 2/3 so it is D. 
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Answer:

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3 years ago
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What are expressions for MN and LN? Hint Construct the altitude from M to LN.
Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x\sqrt{2}  LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle <u>on the left</u> of the altitude:

45+90+angle=180

angle = 45

For the triangle <u>on the right</u>:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

For MN:

\frac{x}{sin(30)} = \frac{MN}{sin(45)}

MN = \frac{x.sen(45)}{sen(30)}

MN = x\sqrt{2}

For LN:

\frac{LN}{sen(105)} =\frac{x}{sin(30)}

LN = \frac{x.sin(105)}{sin(30)}

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = \frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}

sin(105) = \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}

LN = \frac{x.sin(105)}{sin(30)}

LN = x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}  ) .2

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

The expressions for:

MN = x\sqrt{2}

LN = \frac{x}{2}.(\sqrt{2} + \sqrt{6} )

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