So we have
h=hits
m=miss
h+m=10
gain 5 for every hit and lose 3 for every miss
so 5 times number of hit=points from hit
-3 times number of miss=points deducted from miss
add
5h-3m=18
so we have the equations
h+m=10
5h-3m=18
multiply first equation by 3
3h+3m=30
add to first equatio
3h+3m=30
<u>5h-3m=18 +</u>
8h+0m=48
8h=48
divide by 8
h=6
subsitute
h+m=10
6+m=10
subtract 6
m=4
6 hits
4 miss
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Given that quadrilateral QRST is a square.
Each angle of a square is of 90 degrees.
Angle <RQT is also an angle of 90 degrees.
We also given angle RQT = 3x - 6.
So, we can setup an equation as 3x-6 =90.
Now, we need to solve the equation for x.
6 is being subtracted from left side.
We always apply reverse operation. Reverse operation of subtraction is addition.
So, adding 6 on both sides of the equation, we get
3x-6+6 =90+6.
3x = 96.
3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.
So, dividing both sides by 3.

x=32 (final answer).
1 1/4= 1*4+1 /4. Or 5/4
In order to subtract you must have same denominator. 5/4 -3/8
Multiply 5/4 times 2/2. =. 10/8. -3/8
The difference is 7/8
Answer:
17.907082 unit
Step-by-step explanation:
According to the Question,
Given, A circle with centre F, ∠EFG=54 and EF=19 .
length of arc EG = Radius(EF) × ∠EFG(in Radian)
- We Know, 1 degree = 0.0174533 Radian
- 54 degree = 0.942478 Radian
length of arc EG = 19 x 0.942478 ⇔ 17.907082 unit
(For Diagram please find in attachment)
First you start off by setting up a Subtraction problem there anything common denominators of 7/8 and two over three verse 7/8 you should get 21/24 invert to over three you should get 16/24 then you would subtract those two anyway to get 5/24 I hope that was helpful get it