Question

Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's position compared to Quinn?

Answer 1

Answer:

$25\frac{1}{4}$ feet

Step-by-step explanation:

Given

$Maddy = 67\frac{3}{4}$ above Jasmin

$Jasmin = 42\frac{1}{2}$ below Quinn

Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

$z = 67\frac{3}{4}$

$x = 42\frac{1}{2}$

The relationship between x, y and z is

$z = y + x$

Make y the subject of formula

$y = z - x$

Substitute the values of z and x

$y = 67\frac{3}{4} - 42\frac{1}{2}$

Convert to improper fractions

$y = \frac{271}{4} - \frac{85}{2}$

Take LCM

$y = \frac{271 - 170}{4}$

$y = \frac{101}{4}$

$y = 25\frac{1}{4}$

Hence; Maddy's position relative to Quinn's is $25\frac{1}{4}$ feet