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Ymorist [56]
2 years ago
7

P+q=1 and pq=-20. What are the values of p and q?​

Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0

Answer:

Step-by-step explanation:

5, -4

5-4=1

5(-4)=-20

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Please answer asap thank uuuuu
fomenos

Answer:

B

Step-by-step explanation:

4 0
2 years ago
Rename the number to 120,000 ten thousand
Ray Of Light [21]
120,000 renamed to ten thousand (10,000) is twelve ten thousand. Ten thousand in number form is 10,000.  When you divide 120,000 (one hundred and twenty thousand)  by 10,000 (ten thousand) you get 12.  120,000 (one hundred and twenty thousand)  /10,000 (ten thousand) = 12. So there are twelve ten thousands in 120,000.
4 0
2 years ago
HELP PLEASE ILL GIVE BRAINLIEST
iren [92.7K]

The surface of the triangle count formula

A = b*h*1/2

A - area

b - base

c - height

The 1st triangle

A₁ = b₁*h = 6in * 8in *1/2= 24in²


The 2nd triangle

A₂ b₂*h = 10in * 8in*1/2 = 40in²


The total area of the two triangles is 24in² + 40in² = 64 square inches





3 0
3 years ago
6 1/2 - 3 2/5 please help really need it
tatuchka [14]
Answer is 3 1/10 


6 1/2 - 3 2/5 =
13/2 - 17/5 =
65/10 - 34/10 = 
31/10 = 3 1/10
4 0
2 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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