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AleksandrR [38]
3 years ago
13

I need help on number 4 plz

Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0
A measure of center<span> is a value at the </span>center<span> or middle of a </span>data set. Graphically, the center<span> can be viewed as the "balance point" of the display. Algebraically, the most common ways to find the </span>center<span> are with the mean, median, or mode. Mean is the average or sum of all </span>data<span> points divided by the number of points.</span>
aleksklad [387]3 years ago
8 0
The center<span> of a data set is a single number that we can use to stand in for the whole data set. You can usually think of it as a "typical" value. We usually use </span>mean<span> or </span>median<span> for the center. The median is often a better "typical" value if the distribution is skewed (that is, grossly asymmetrical).</span>
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Cushman Company had $824,000 in sales, sales discounts of $12,360, sales returns and allowances of $18,540, cost of goods sold o
Tpy6a [65]

Answer:

$118,245

Step-by-step explanation:

So we just subtract everything ffrom 824,000 to find the net income

When you subtract everything you should get 118,245

5 0
3 years ago
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If the hypotenuse of a right triangle measures 15 cm and one of the legs measures 12 cm, what is the length of the other leg?
Mama L [17]

Step-by-step explanation:

12 to the 2nd power=144

15 to the 2nd power =225

225-144=81

square root of 81 is 9

5 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
Convert -3(4+7) to word statements
Alex787 [66]

Answer:

-14

Step-by-step explanation:

4+7=11 so therefore -3-11=-14

3 0
3 years ago
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This graph shows the amount of charge left on my
prisoha [69]

Answer:

c= -20h + 90

Step-by-step explanation:

7 0
3 years ago
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