Answer:
12/25 or 48% or 0.48
Step-by-step explanation:
There are 12 even numbers.
25 is good for percentages because you can just multiply it by four to get to 100
From an acceleration-time graph, you can work out the area under the graph to find the velocity. There are two triangles on the graph as shown below. The total area of the triangles are
![\frac{(10)(10)}{2}+ \frac{(20)(20)}{2}=250 ft/sec^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%2810%29%2810%29%7D%7B2%7D%2B%20%5Cfrac%7B%2820%29%2820%29%7D%7B2%7D%3D250%20ft%2Fsec%5E%7B2%7D%20)
Hence, the distance is 250×30=7500 ft
Answer:
(-3, 2)
Step-by-step explanation:
{3x=7y=5
{5x-2y=-19
solve....
maybe it was 3x + 7y = 5
and 5x - 2y = -19
2*(3x + 7y = 5)
7*(5x - 2y = -19)
-------------
6x + 14y = 10
35x -14y = -133
41x = -123
x = -3
y = ...
5*(-3) - 2y = -19
-15 - 2y = -19
2y = 4
y = 2
(-3, 2)
Answer:
The equation is not linear
Step-by-step explanation:
You are given the equation
![\dfrac{2}{x}+\dfrac{y}{4}=\dfrac{3}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7Bx%7D%2B%5Cdfrac%7By%7D%7B4%7D%3D%5Cdfrac%7B3%7D%7B2%7D)
Express y in terms of x:
![\dfrac{y}{4}=\dfrac{3}{2}-\dfrac{2}{x}\\ \\\dfrac{y}{4}=\dfrac{3x-4}{2x}\\ \\y=4\cdot \dfrac{3x-4}{2x}\\ \\y=\dfrac{6x-8}{x}](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7B4%7D%3D%5Cdfrac%7B3%7D%7B2%7D-%5Cdfrac%7B2%7D%7Bx%7D%5C%5C%20%5C%5C%5Cdfrac%7By%7D%7B4%7D%3D%5Cdfrac%7B3x-4%7D%7B2x%7D%5C%5C%20%5C%5Cy%3D4%5Ccdot%20%5Cdfrac%7B3x-4%7D%7B2x%7D%5C%5C%20%5C%5Cy%3D%5Cdfrac%7B6x-8%7D%7Bx%7D)
The linear function must of form
![y=mx+b,](https://tex.z-dn.net/?f=y%3Dmx%2Bb%2C)
where m and b are real numbers.
Your function is not of this form, so this is not a linear function.
Answer:
The vertical height is ![h=3\ units](https://tex.z-dn.net/?f=h%3D3%5C%20units)
Step-by-step explanation:
we know that
In the right triangle ABC
see the attached figure
To find the height h apply the Pythagoras Theorem
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
we have
![c=AB=3\sqrt{2}\ units](https://tex.z-dn.net/?f=c%3DAB%3D3%5Csqrt%7B2%7D%5C%20units)
![a=BC=6/2=3\ units](https://tex.z-dn.net/?f=a%3DBC%3D6%2F2%3D3%5C%20units)
![b=AC=h\ units](https://tex.z-dn.net/?f=b%3DAC%3Dh%5C%20units)
substitute
![(3\sqrt{2})^{2}=3^{2}+h^{2}](https://tex.z-dn.net/?f=%283%5Csqrt%7B2%7D%29%5E%7B2%7D%3D3%5E%7B2%7D%2Bh%5E%7B2%7D)
![18=9+h^{2}](https://tex.z-dn.net/?f=18%3D9%2Bh%5E%7B2%7D)
![h^{2}=18-9=9](https://tex.z-dn.net/?f=h%5E%7B2%7D%3D18-9%3D9)
![h=3\ units](https://tex.z-dn.net/?f=h%3D3%5C%20units)