Answer:

Step-by-step explanation:
The radius r can be found from the relationship

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

See the attached image.
Answer:
The intersection of both lines.
<span>Since charged particles cannot move across the membrane easily due to them being hydrophobic, they require a transport protein that expends energy in the form of ATP. ATP attaches onto the transport protein which changes the shape of the protein allowing ions to flow in, and it leaves a phosphate group turning into ADP.When the molecule has crossed the membrane, the phosphate group is detached from the protein.</span>
Answer:
a=3
Step-by-step explanation:
This should be very simple, just substitute xy and y for 5 and 7 respectively, so 5a-2*7=1, or 5a-14=1, or 5a=15, if we divide both sides by 5, we get a=3