Given:
The figure of a right angle triangle.
Hypotenuse = 
in.
To find:
The missing lengths of the sides.
Solution:
In the given right angle triangle both legs a and b are equal, and hypotenuse is in.
Using Pythagoras theorem, we get
![[\because a=b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%3Db%5D)
Divide both sides by 2.
Taking square root on both sides.
Side cannot be negative. So,
Thus, the missing side lengths are a=9 in and b=9 in.
Therefore, the correct option is C.
Answer:
24
Step-by-step explanation:
3(2n-8)=5n distribute 3
6n-24=5n combine like terms
-24=-n divide by -1 on both sides
24=n
n=24
Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
![6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}](https://tex.z-dn.net/?f=6%5Ccdot%5Cfrac%7B1%7D%7B2%7D%5Ccdot6%5Ccdot%5Csqrt%5B%5D%7B63%7D%3D18%5Csqrt%5B%5D%7B63%7D)
Answer:
Step-by-step explanation:
Quadratic equations of the form (x - h)^2 + k = 0 can be solved using square roots: Take the square root of both sides, prefacing the right side with " ± "
Answer:
x g(x)
1 −10
2 −12
3 −14
Step-by-step explanation:
Substitute the values and do the arithmetic.
Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.
f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic
g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice
