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Ad libitum [116K]
2 years ago
8

A baker mixes a 21-pound batch of dough that contains 3 pounds of sugar. Approximately how many pounds of sugar must be added fo

r the dough to contain 27% sugar?
A. 2.7 B. 3.1 C. 3.6 D. 4.2
Mathematics
1 answer:
scZoUnD [109]2 years ago
7 0
The answer is c. 3.6

3.6 + 3 = 6.6 pounds of sugar
6.6-3 = 3.6 pounds of sugar added to the dough. This weight that must be added to the total weight of the dough.
3.6 (new sugar) +21 (original dough weight) = 24.6 (total weight)

6.6/24.6 = 26.8%
You might be interested in
Which statement is true?
Lady_Fox [76]

Answer:

An irrational number may show terminating digits after the decimal

Step-by-step explanation:

Examples of Rational Numbers

Number 9 can be written as 9/1 where 9 and 1 both are integers.  0.5 can be written as ½, 5/10 or 10/20 and in the form of all termination decimals.  √81 is a rational number, as it can be simplified to 9 and can be expressed as 9/1.  0.7777777 is recurring decimals and is a rational number

Examples of Irrational Numbers

Similarly, as we have already defined that irrational numbers cannot be expressed in fraction or ratio form, let us understand the concepts with few examples.

5/0 is an irrational number, with the denominator as zero.

π is an irrational number which has value 3.142…and is a never-ending and non-repeating number.

√2 is an irrational number, as it cannot be simplified.

0.212112111…is a rational number as it is non-recurring and non-terminating.

There are a lot more examples apart from above-given examples, which differentiate rational numbers and irrational numbers.

Properties of Rational and Irrational Numbers

Here are some rules based on arithmetic operations such as addition and multiplication performed on the rational number and irrational number.

#Rule 1: The sum of two rational numbers is also rational.

Example: 1/2 + 1/3 = (3+2)/6 = 5/6

#Rule 2: The product of two rational number is rational.

Example: 1/2 x 1/3 = 1/6

#Rule 3: The sum of two irrational numbers is not always irrational.

Example: √2+√2 = 2√2 is irrational

2+2√5+(-2√5) = 2  is rational

#Rule 4: The product of two irrational numbers is not always irrational.

Example: √2 x √3 = √6 (Irrational)

√2 x √2 = √4 = 2 (Rational)

5 0
3 years ago
Use the real zeros to factor f x^4 plus 10^3 minus 20x^2 minus 90x plus 99
Furkat [3]

Answer:

f(x) = (x + 11) (x + 3) (x − 1) (x − 3)

Step-by-step explanation:

f(x) = x⁴ + 10x³ − 20x² − 90x + 99

f(x) is a fourth order polynomial, so it has 4 roots.  Use rational root theorem to find possible rational roots.

±99, ±11, ±9, ±3, ±1

By trial and error, the zeros are -11, -3, 1, and 3.

f(x) = (x + 11) (x + 3) (x − 1) (x − 3)

7 0
3 years ago
28. The edges of a cube are all increased by
Zolol [24]

Answer:

Percentage increase in volume will be

33.1

%

Step-by-step explanation:

Let the each edge of cube be

100

units.

Then its volume is

100

3

=

1000000

cubic units.

If each edge increases by

10

%

it becomes

110

units

and volume becomes

110

3

=

1331000

cubic units

Therefore increase in volume is

1331000

−

1000000

=

331000

cubic units

and percentage increase in volume is

331000

1000000

×

100

%

=

331

10

%

=

33.1

%

7 0
3 years ago
Kelly was asked to determine whether △KLN is congruent to △MNL. She noted that KL ≅ MN, LM ≅ KN, and that the three pairs of cor
Art [367]

Answer:

<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>

Step-by-step explanation:

To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.

  • Angle-Angle-Side Theorem (AAS theorem).
  • Hypotenuse-Leg Theorem (HL theorem).
  • Side-Side-Side Postulate (SSS postulate).
  • Angle-Side-Angle Postulate (ASA postulate).
  • Side-Angle-Side Postulate (SAS postulate).

In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.

So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)

8 0
3 years ago
Simplify square root of negative 48
77julia77 [94]
\bf \sqrt{-48}\qquad &#10;\begin{cases}&#10;48=2\cdot 2\cdot 2\cdot 2\cdot 3\\&#10;\qquad 2^2\cdot 2^2\cdot 3\\&#10;\qquad (2^2)^2\cdot 3&#10;\end{cases}\implies \sqrt{-1\cdot (2^2)^2\cdot 3}&#10;\\\\\\&#10;\sqrt{-1}\cdot \sqrt{(2^2)^2\cdot 3}\implies i\cdot 2^2\sqrt{3}\implies 4\sqrt{3}\ i
5 0
3 years ago
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