Answer: x = -3/4 can not be a rational zero of the polynomial.
Step-by-step explanation:
We have the polynomial:
6x^5 + ax^3 -bx -12 = 0.
The theorem says that:
If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).
The factors of -12 (different than itself) are (independent of the sign).
1, 2, 3, 4 and 6.
So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.
The factors of 6 are:
1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.
Then the option that can not be a zero of the polynomial is
x = -3/4
because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.
I am assuming that you mean
and
Now, let's look for common factors. The first one is
After we take that out, we are left with 14 and 22. We can take a 2 out of both of these, so the greatest common factors is
First you have to get the variable to one side.
To do this you have to subtract 2/3x from both sides.
4/3x-2/3x=2/3x
Now you have:
1/6=2/3x
Divide by 2/3
1/6÷2/3=1/6×3/2=3/12=1/4
Your answer is:
X=1/4
Based on the short-term debt that Nelson raises, the firm's quick ratio will be 1.204.
<h3>What is the firm's quick ratio?</h3><h3 />
First, find the maximum amount of short-term funds that Nelson can raise?
Assuming this amount is x, we can find it with the current ratio formula:
Current ratio = Current assets / Current liabilities
2 = (1,260,000 + x) / ( 450,000 + x)
x = $360,000
The quick ratio would therefore be:
= ( New Current assets - New inventory) / New current liabilities
= ( (1,260,000 + 360,000) - (285,000 + 360,000) ) / (450,000 + 360,000)
= 1.204
Find out more on quick ratio at brainly.com/question/13917900.
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Answer:
A. 5.8
Step-by-step explanation:
From the given graph d has two coordinates;
the first coordinates of d = (0, 0)
the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal
The distance between the two coordinates = distance of d;
Option A is correct
