Question

In August 2009, the classified ads for used cars listed a 3-year old Cadillac for $24,000

Answer 1

Answer:

$V=-2,000a+30,000$

Step-by-step explanation:

Let V be the value of the car and a be the age of the car.

When a = 3, V = $24,000. So, we get the point (3, 24,000).

When a = 11, V = $8,000. So, we get the point (11, 8,000).

Write the equation of the line passing through these points:

$\dfrac{V-8,000}{24,000-8,000}=\dfrac{a-11}{3-11}\\ \\\dfrac{V-8,000}{16,000}=\dfrac{a-11}{-8}\\ \\V-8,000=-\dfrac{16,000}{8}(a-11)\\ \\V-8,000=-2,000(a-11)\\ \\V=-2,000a+22,000+8,000\\ \\V=-2,000a+30,000$