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3 years ago

15

Please answer the circled questions below!

1 answer:

Anton [14]3 years ago

8 0

Answer:

Step-by-step explanation:

1. The y-values in the table are constant, so the slope is 0. It is a horizontal line.

There is no x-intercept.

The y-intercept is (0, 1).

__

For lines in standard form, the intercepts can be found easily. The x-intercept is the value of x when y=0:

ax +0 = c

x = c/a . . . . x-intercept

Similarly, the y-intercept is the value of y when x=0:

0 +by = c

y = c/b

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3. x-intercept = (-20/2, 0) = (-10, 0)

y-intercept = (0, -20/-5) = (0, 4)

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4. x-intercept = (-6/1, 0) = (-6, 0)

y-intercept = (0, -6/-3) = (0, 2)

Plot these points and draw a line through them.

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Please I need help on this ASAP

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Answer:

$\frac{1}{256}$

Step-by-step explanation:

$\frac{1}{16} \times \frac{1}{16} = \frac{1}{256}$

there are 16 classmates in total including bess and caroline. and there chances as one person is 1 out of those 16 classmates.

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Geometric mean between 9 and 36

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7 less than a number k is 18

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A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

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3 years ago