<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Do you know the muffin man 2*+%9272
Answer:
answer is a
Step-by-step explanation:
answer would be a because a reflection does not change the size or shape of any figure
Answer:
19/30
Step-by-step explanation:
1/5 + 2/15 + 3/10
We need the LCD of 5, 15, and 10.
LCD = 30
1/5 + 2/15 + 3/10 =
= 6/30 + 4/30 + 9/30
= 19/30
Answer: 19/30
Answer:
-1/2
Step-by-step explanation:
2/6 - 5/6= -3/6
= -1/2
