133 112
---- = -------
x 16
112x = 133 . 16
112x = 2128
x = 2128/112
x = 19
answer: x = 19
What you do is:
Convert 3 2/3 into an improper fraction
Multiplying the whole number to the denominator, of which the total is added by the numerator
The denominator stays the same whilst the numerator is the new total = 11
So it'll be 11/3
Now you see that you must find the sum of 11/3 + 5/4
Find the LCM of both denominators, which 12, multiplying the amount needed to make them twelve to the numerators.
You then get:
44/12 + 15/12 = 59/12
59/12 --> 2 11/12
(7+3) x n = 16
pretty sure that is right.
Answer:
3
Step-by-step explanation:
We are given an expression and are asked how many terms are there.
When it comes to terms, we need to see how many numbers have different endings, this can be variables, symbols, and exponents.
Looking into it, we see 4x^2 - 3x + 2
These are all different terms, therefore there are 3 different terms.
Answer:
The half life of the substance is 
.
Step-by-step explanation:
The equation that models the amount of substance after time 
is
.
We are told that that the initial amount 
, and the k-value is 
; therefore,
The half-life of the substance is the amount of time 
it takes to decay to half its initial value; therefore,
Take the Natural Logarithm of both sides and get:
![ln[e^{-0.1481\tau } ]= ln[\dfrac{1}{2}]](https://tex.z-dn.net/?f=ln%5Be%5E%7B-0.1481%5Ctau%20%7D%20%5D%3D%20ln%5B%5Cdfrac%7B1%7D%7B2%7D%5D)
![-0.1481\tau = ln[\dfrac{1}{2} ]](https://tex.z-dn.net/?f=-0.1481%5Ctau%20%3D%20ln%5B%5Cdfrac%7B1%7D%7B2%7D%20%5D)
![\tau = \dfrac{ln[\dfrac{1}{2} ]}{-0.1481}](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20%5Cdfrac%7Bln%5B%5Cdfrac%7B1%7D%7B2%7D%20%5D%7D%7B-0.1481%7D)
Thus, we find that the half life of the substance is 4.7 days.
