Ask question

Ask question

All categories

3 years ago

9

I need help on these what is 5=g-8

1 answer:

Levart [38]3 years ago

7 0

The answer is g=13 I hope this helped

You might be interested in

The probability mass function of X is f(x)= 1/6, x 1.2...,6 then find out the value

Mumz [18]

For the given probability mass function of X, the mean is 3.5 and the standard deviation is 1.708.

A discrete random variable X's probability mass function (PMF) is a function over its sample space that estimates the likelihood that X will have a given value. f(x)=P[X=x].
The total of all potential values for a random variable X, weighted by their relative probabilities, is known as the mean (or expected value E[X]) of that variable.
Mean(μ) = 1(1/6) + 2(1/6) + 3(1/6) + 4(1/6) + 5(1/6) + 6(1/6).
Mean(μ) = (1+2+3+4+5+6)/6
Mean(μ) = 21/6
Mean(μ) = 3.5
The square root of the variance of a random variable, sample, statistical population, data collection, or probability distribution represents its standard deviation. It is denoted by 'σ'.
A random variable's variance (or Var[X]) is a measurement of the range of potential values. It is, by definition, the squared expectation of the distance between X and μ. It is denoted by 'σ²'.
σ² = E[X²]−μ²
σ² = [1²(1/6) + 2²(1/6) + 3²(1/6) + 4²(1/6) + 5²(1/6) + 6²(1/6)] - (3.5)²
σ² = [(1² + 2²+ 3² + 4²+ 5²+ 6²)/6] - (3.5)²
σ² = [(1 + 4 + 9 + 16 + 25 + 36)/6] - (3.5)²
σ² = (91/6) - (3.5)²
σ² = 15.167-12.25
σ² = 2.917
σ = √2.917
Standard deviation (σ) = 1.708

To learn more about variance, visit :

brainly.com/question/14116780

#SPJ9

6 0

2 years ago

PLEASE HELP! GRAPH THE FUNCTION

algol [13]

#8

y=4(x-0)²+0

Vertex at (0,0)

#11

y=-6(x-0)²+0

Same Vertex

#14

y=-(x-0)²+2

Vertex (0,2)

8 0

2 years ago

Read 2 more answers

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

marishachu [46]

Answer:

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2-6=-x$

This can be written as , $x^2+x-6=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = 1 , c = -6

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(1)\pm\sqrt{(1)^2-4\cdot 1 \cdot (-6)}}{2 \cdot 1}$

$\Rightarrow x=\frac{-1\pm\sqrt{25}}{2}$

$\Rightarrow x=\frac{-1\pm 5}{2}$

$\Rightarrow x_1=\frac{-1+5}{2}$ and $\Rightarrow x_2=\frac{-1-5}{2}$

$\Rightarrow x_1=\frac{4}{2}$ and $\Rightarrow x_2=\frac{-6}{2}$

$\Rightarrow x_1=2$ and $\Rightarrow x_2=-3$

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

7 0

3 years ago

Read 2 more answers

Please help. Only answer if you know, please.

nevsk [136]

Answer: is this high school

Step-by-step explanation:

5 0

3 years ago

Drag each tile to the correct box.

Hunter-Best [27]

Answer:

Step-by-step explanation:

6 0

2 years ago