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4 years ago

What is the answer for 10+2(10n+4)

Mathematics

2 answers:

Gekata [30.6K]4 years ago

8 0

Hey there!

$Answer:\boxed{20n+18}$

$Explanation:$

$10+2(10n+4)$

Let's start by distributing.

$10+(2)(10n)+(2)(4)\\10+20n+8$

Now combine like terms.

$10+20n+8\\(20n)+(10+8)\\20n+18$

$\boxed{20n+18}\text{ is the answer.}$

Hope this helps!

$\text{-TestedHyperr}$

SashulF [63]4 years ago

4 0

Answer:

20n + 18

Step-by-step explanation:

10 + 2(10n + 4)

10 + 20n + 8

20n + 18

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How do you solve this?

shutvik [7]

Answer: X=5

Step-by-step explanation:

-8=(X+11)/-2

* start by multiplying both sides by -2

16=X+11

*subtract 11 from both sides

5=X

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4 years ago

For what values of x is x^2 + 2x = 24 true?

maw [93]

Answer:

$x = -6, x = 4$

Step-by-step explanation:

Step 1: Factor

Subtract 24 from both sides

$x^2 + 2x- 24 = 24 - 24$

$x^2 + 2x - 24 = 0$

Make two different x's

$x^2 + 2x - 24 = 0$

$x^2 + 6x - 4x - 24 = 0$

Make two different parenthesis

$x^2 + 6x - 4x - 24 = 0$

$(x + 6)(x - 4) = 0$

Step 2: Solve for x in both equations

$x + 6 = 0$

$x + 6 - 6 = 0- 6$

$x = -6$

$x - 4 = 0$

$x - 4 + 4 = 0 + 4$

$x = 4$

Answer: $x = -6, x = 4$

6 0

3 years ago

Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)

Xelga [282]

Answer:

$\frac{x^2}{16}-\frac{b^2}{4}=1$

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4$

The foci c is at +/-2√5, using c² = a² + b²:

$c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2$

Substituting the value of a and b to get the equation of the hyperbola:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1$

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3 years ago

The box is 7.5 inches

SVEN [57.7K]

Answer:37.5 square inches

Step-by-step explanation:

7 0

3 years ago

M2=(y+10)° and m4=(3y-24)° what is m<2 show all of your work.

Ivan

Step-by-step explanation:

m∠2 = m∠4

y + 10 = 3y - 24

y - 3y = -24 - 10

-2y = -34

y = -34/-2

y = 17

m∠2 = y + 10

m∠2 = 17 + 10

m∠2 = 27°

6 0

3 years ago

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