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vivado [14]
3 years ago
7

When is the magnetic field the strongest?

Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0
When it's by the magnetic poles
sveticcg [70]3 years ago
6 0
When it is closest to another magnetic field

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Factorise them please
Shalnov [3]

Answer:

2x+10 = 2(x+5)

5x-15 = 5(x-3)

8x+6 = 2(4x+3)

12x-8 = 4(3x-2)

-HOPE IT HELPS-


Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Parallelogram TUVW is graphed on a coordinate plane with vertices at T (3, 4), V (-10,-2), V(-6,5),
zalisa [80]

The coordinates of the dilated vertex V' is (-6p, 5p)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, reflection, rotation and dilation.</em>

<em />

Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

The Parallelogram TUVW has vertices at T(3, 4), U(-10,-2), V(-6,5) and  W (7,11). If it is dilated by a scale factor p with the origin, the new point is at:

T'(3p, 4p), U'(-10p, -2p), V'(-6p, 5p) and W'(7p, 11p)

Find out more on dilation at:brainly.com/question/10253650

3 0
2 years ago
Given: AABC, AC = 5<br> m C = 90°<br> m A= 22°<br> Find: Perimeter of AABC<br> A<br> C<br> B
Leto [7]

9514 1404 393

Answer:

  perimeter ≈ 12.4 units

Step-by-step explanation:

The side adjacent to the angle is given. The relationships useful for the other two sides are ...

  Tan = Opposite/Adjacent

  Cos = Adjacent/Hypotenuse

From these, we have ...

  opposite = 5·tan(22°) ≈ 2.02

  hypotenuse = 5/cos(22°) ≈ 5.39

Then the perimeter is ...

  P = a + b + c = 2.02 + 5 + 5.39 = 12.41

The perimeter of ∆ABC is about 12.4 units.

7 0
2 years ago
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
4. Look at these prices.
Snowcat [4.5K]
7.89 7.98 8.79 8.97
7 0
3 years ago
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