The Pyth. Thm. applies here:
(√x + 1)^2 + (2√x)^2 = (2√x + 1 )^2
Expanding the squares:
x + 2sqrt(x) + 1 + 4x = 4x + 4sqrt(x) + 1
Let's subtract x + 2sqrt(x) + 1 + 4x from both sides:
4x + 4sqrt(x) + 1
-(x + 2sqrt(x) + 1 + 4x)
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3x + 2sqrt(x) - 4x = 0
Then 2sqrt(x) = x
Squaring both sides, 4x = x^2, or x^2 - 4x = 0. Then (x-4)x = 0, and the two possible solutions are 0 and 4.
Check these results by substitution. Does the Pyth. Thm. hold true for x=4?
Answer:
282.4
Step-by-step explanation:
V=1/3 pi Bh where B is the area of the base and h is the height
V=1/3 (3.14159)(10.6)^2(2.4)=282.4
Answer:
26
Step-by-step explanation:
To find the area of the three combined shapes, multiply the length times the width of each and add them together. Five times two is 10, and since there are two identical rectangles (the top and the bottom one), the current combined area is 20. Three times two is 6. 20 + 6 = 26.
Answer:
3.75
Step-by-step explanation:
1.25x3=3.75 easy. you just need to times the height by length
