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Pavlova-9 [17]
3 years ago
13

Suppose a study of population 400,000 has been growing at rate of 7% per year if this rate continues find the population of this

city in 10 years the population in 10 years will be approximately
Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

680,000

Step-by-step explanation:

Population before growing rate: 400,000

Growing rate: 7%

Duration: 10 years

___

First, you will have to calculate how much does the population increase each year with the said rate, so you will have to multiply the rate by the population to determine that amount.

400,000 x 7/100 = 28,000

So the population increases by 28,000 each year, now you will have to multiply that amount by the amount of years to determine how much the amount of increase.

28,000 x 10 = 280,000

This means that the population has increased by 280,000 in these 10 years. Finally, you will have to add that number to the population amount to get the answer.

400,000 + 280,000 = 680,000

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7 0
4 years ago
Find the point of intersection for the two functions through substitution. Show
Alex777 [14]
<h3>Answer:  (-1, 11)</h3>

This means x = -1 and y = 11 pair up together.

================================================

Work Shown:

Set the two functions equal to one another. Solve for x.

f(x) = g(x)

-4x+7 = 2x+13

7 = 2x+13+4x ... adding 4x to both sides

7 = 6x+13

7-13 = 6x .... subtract 13 from both sides

-6 = 6x

6x = -6

x = -6/6 ... divide both sides by 6

x = -1

Use this x value in either function

f(x) = -4x+7

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or

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Whichever function you pick, the input x = -1 leads to the output y = 11.

The point of intersection is (x,y) = (-1, 11)

Visual confirmation is shown below.

4 0
3 years ago
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