1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
3 years ago
13

in a fundraising committee of 90 people the ratio of men to women is 7:2. find the number of women required to join the existing

committee so that the ratio of men to women is 5:4​
Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0

Hello,

Step-by-step explanation:

90 = 9 x 10 = (7 + 2) x 10 = 70 + 20

70 men and 20 women

\frac{70}{5}  = \frac{20 + X}{4}

56 = 20 + X ⇔ X = 36

Answer : + 36 women

You might be interested in
Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is −6?
ikadub [295]
Line M with slope 6 is neither, line n with slope -6 is parallel because only lines with same slope are parallel, line p with slope 1/6 is neither. and line q with slope -1/6 is perpendicular because only the reciprocal of a slope is perpendicular, so reciprocal of 6= 1/6 reciprocal of -6=-1/6 reciprocal of 2= 1/2
8 0
3 years ago
Read 2 more answers
Did you hear about the two punsters who told a lot of jokes about cats
Serggg [28]
Ooo. I I didn't hear please do tell
4 0
4 years ago
a band that will be the opening act for a concert charges a $700.00 flat fee as well as 16% of all ticket profits from ticket sa
Fofino [41]
The band earned $1,200.

1. Subtract the flat fee 1,200-700 =500
2. 500 is what just the band made. Divide that by .16 (16%) to get the total ticket amount... 500 divided by .16 = 3,125

The total ticket amount was $3,125.
5 0
3 years ago
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and ob
klio [65]

Answer:

Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.

A.  The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.

C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.

E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake

The answer is E.

6 0
3 years ago
ALOT OF POINTS THIS IS IMPORTANT DO FAST PLSSS PLSSSSSSSSSSSS'
IrinaK [193]

Answer:

he has 350 dollar with interest

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Other questions:
  • PLZZ HELP URGENT
    10·2 answers
  • A spinner with 9 equal sections is numbered 1 through 9. The probability of spinning a 1 or a 9 is 2/9 .
    6·2 answers
  • Is 2/5 greater than or less than 4/5?
    6·2 answers
  • A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
    5·1 answer
  • Describe 59 in two other ways
    5·1 answer
  • The shipping department must send out 50 cases of phones. Five stores will receive ten cases each. How many cases are left?
    6·2 answers
  • Which measurements could NOTrepresent the side lengths of a right triangle?
    15·2 answers
  • Help please! Greatly appreciated if you do!
    9·2 answers
  • Find the midpoint of the line segment with the endpoints A and B.
    7·1 answer
  • Which statement describes the graph of g(x) with respect to the graph of f(x)?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!