Answer:
x = 76.58°
Step-by-step explanation:
hyp = 13.41
tan = opp/adj
tan = 1/2 = 26.57
x = 76.58
Answer:
yes
Step-by-step explanation:
but really nice to the world I'm happy for you because you is so buetiful
Use PEMDAS for this problem.
1 x 1000= + 1000
3 x 10,000= 30,000
---------------------------
+ 31000
9000
---------------------------
+ 40000
800
--------------------------
+ 40800
50
------------------------------
+ 40850
2
------------------------------
Answer: 40,852
Hoped this helped.
~Bob Ross ®
answer is c ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
