A rectangular solar panel has a length that is 12 inches shorter than 3 times its width. If the perimeter of the panel is 160 i
nches, what are the dimensions of the panel?
1 answer:
Answer:
width = 23 inches
length = 57 inches
Step-by-step explanation:
Let x inches be the width of the rectangular solar panel.
So,
width = x inches
3 times the width = 3x inches
12 inches shorter than 3 times the width = 3x - 12 inches
length = 3x - 12 inches
The perimeter of the rectangle is
Hence,
![160=2(x+3x-12)\\ \\160=2(4x-12)\\ \\80=4x-12\ [\text{Divided by 2}]\\ \\4x=80+12\\ \\4x=92\\ \\x=23\ inches\\ \\3x-12=3\cdot 23-12=69-12=57\ inches](https://tex.z-dn.net/?f=160%3D2%28x%2B3x-12%29%5C%5C%20%5C%5C160%3D2%284x-12%29%5C%5C%20%5C%5C80%3D4x-12%5C%20%5B%5Ctext%7BDivided%20by%202%7D%5D%5C%5C%20%5C%5C4x%3D80%2B12%5C%5C%20%5C%5C4x%3D92%5C%5C%20%5C%5Cx%3D23%5C%20inches%5C%5C%20%5C%5C3x-12%3D3%5Ccdot%2023-12%3D69-12%3D57%5C%20inches)
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Answer:
720 sq ft
Step-by-step explanation:
Formula:
2 B + P x H
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so 3%of x + 4% of (3000-x) = 107
By solving x = 1300
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second investment is 1700
