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3 years ago

Find the sum of the infinite series1/3+4/9+16/2764/81... if it exists.

Mathematics

1 answer:

nata0808 [166]3 years ago

8 0

Answer:

It does not exist.

Step-by-step explanation:

If we divide the second term by the first, 3rd by the 2nd and the 4th by the 3rd we get a constant result 4/3.

So this is a Geometric Series with common ratio r = 4/3 and a1 = 1/3.

As the common ratio is greater than 1 the series diverges ( continues to get bigger) so there is no sum to infinity. It just goes on getting bigger and bigger without bounds.

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(1/2)2 = base y exponente

Vladimir [108]

Divides el (1/2) q es 2 pq 2*1=2 y después multiplicas 2*2=4 entonces la respuesta es 4 y es base creo

4 0

2 years ago

Pat’s softball team won 5 games for every 3 games they lost.

Vera_Pavlovna [14]

Answer:

20 games were won and 12 games were lost.

Step-by-step explanation:

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2 years ago

Read 2 more answers

How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation

mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

$|a|\geq0$

for any real value of a.

|a| = b > 0 - two solutions: a = b or a = -b

|a| = 0 - one solution: a = 0

|a| = b < 0 - no solution

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5 add 4 to both sides

|x + 6| = 9 > 0 TWO SOLUTIONS

for c = -10

|x + 6| - 4 = -10 add 4 to both sides

|x + 6| = -6 < 0 NO SOLUTIONS

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 subtract 6 from both sides

x = 3 or x = -15

5 0

2 years ago

Is the Y value of the vertex of 4x squared plus 8X minus 8. help meee

SIZIF [17.4K]

Answer:

y = -12

Step-by-step explanation:

You first calculate the x coordinate using the equation x = $\frac{-b}{2a}$ , which in this case is $\frac{-8}{8} = -1$ .

Then plug that x value into the equation to get the y coordinate:

4(-1)²+8(-1)-8 = -12

8 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago

Find the sum of the infinite series1/3+4/9+16/2764/81... if it exists.​

Find the sum of the infinite series1/3+4/9+16/2764/81... if it exists.