Answer:
Provide an opportunity for the patient to talk about concerns
Explanation:
More often than not, details regarding incoming surgeries are unaddressed without any ill intention, but just because the physician is not aware of some of the patient's worries.
In fact a recent study carried on by listening to a series of audio recordings of patient-physician visits provided an insight that also showed that some behaviors in the pre-op consultation lead to the patient not disclosing all of his/her concern. For example, physicians often redirect patients at the beginning of the visit, giving patients less than 30 seconds to express their concerns.
By including the patient in the decision making process, showing empathy, giving clinical recommendations, going through the surgery's agenda with the patient, and giving the patient time and patience to talk about concerns, the pre-op fear will be reduced and even the post-op treatment has more chances of being completed to the letter.
Answer:
opportunity cost, the elderly woman is alsotaking a cost by not doing nothing as it renounce to doing the walks to obtain safety at home.
Under economics concepts everything has at least one opportunity cost associated with it.
Explanation:
The opportunity cost represent the best alternative we renounce for the given course of action or use of the resources.
In this case not going to walk has the cost walking.
The strategyn Ralston Purina used is called Trading Up.
Trading up is making the number of features in a product that increases. For an example, making it's quality better, adding extra details etc. They do that sometimes to make the price of their product to go up.
Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:
Restrictions:
- High-grade ore: 
- Medium-grade ore: 
- Low-grade ore: 
- No negative hours: 
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.
To solve:
Total cost of merchandise = [(purchased merchandise - returned merchandise) x percentage out of hundred - 1] + transportation cost
Total cost of merchandise = [($4,300 - $295 ) .99] + $380
Total cost of merchandise = ($4,005)(.99) + $380
Total cost of merchandise = $3,964.95 + $380
Total cost of merchandise = $4,344.95
