3 in3.62 stands for 3
1 answer:
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Part A:
Derrick is incorrect.
A yard is equivalent to 3 feet.
Thus, 20 yards will be equivalent to 60 feet.
The width is 20 yard and 2 feet. It's the same as 60 feet and 2 feet, or 62 feet. Thus, Derrick is incorrect.
Part B:
Let's calculate the area of the parking lot.
We know the width is 62 feet from part A.
The length is 30 yards, or 90 feet.
Multiply the length and width to get the area in square feet.
The parking lot has an area of 5580 square foot.
It costs 2 dollars per square foot to repave the parking lot. Multiply the area by 2 dollars.
It will cost $11,160 to repave the whole parking lot.
Derrick is incorrect.
A yard is equivalent to 3 feet.
Thus, 20 yards will be equivalent to 60 feet.
The width is 20 yard and 2 feet. It's the same as 60 feet and 2 feet, or 62 feet. Thus, Derrick is incorrect.
Part B:
Let's calculate the area of the parking lot.
We know the width is 62 feet from part A.
The length is 30 yards, or 90 feet.
Multiply the length and width to get the area in square feet.
The parking lot has an area of 5580 square foot.
It costs 2 dollars per square foot to repave the parking lot. Multiply the area by 2 dollars.
It will cost $11,160 to repave the whole parking lot.
You can solve this analytically to get
.. 55000*(1 +x/100)^10 = 108193
.. (1 +x/100)^10 = 108193/55000
.. 1 +x/100 = (108193/55000)^(1/10)
.. x = 100*((108193/55000)^(1/10) -1) ≈ 7.00
but I find it just as fast to have a graphing calculator do it.
The city's population is increasing 7% per year.
.. 55000*(1 +x/100)^10 = 108193
.. (1 +x/100)^10 = 108193/55000
.. 1 +x/100 = (108193/55000)^(1/10)
.. x = 100*((108193/55000)^(1/10) -1) ≈ 7.00
but I find it just as fast to have a graphing calculator do it.
The city's population is increasing 7% per year.