Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so

2 + 7 - 9 + 11
= 9 - 9 + 11
= 0+ 11
= 11
hope it's helpful !
have a nice day :)
Answer:
3rd choice
Step-by-step explanation:
(7y^6)(2y^-4)^2
= (7y^6)(4y^-8)
Calculate:
(7y^6) * (4y^-8)
28y^-2
Express with a positive exponent:
28 * 1/y^2
As there is no x axis it will have to be vertical as the y axis is already vertical
Let, the number = x
It would be: x + 15 = 2x - 56
2x - x = 15 + 56
x = 71
In short, Your Answer would be 71
Hope this helps!