First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
(1/4ab)^-2
Remove negative exponent by rewritten the equation as (4ab)^2
AUse Product rule to get:
4^2a^2b^2
Now raise 4 to the second power to get:
16a^2b^2
The last answer is correct.
Answer: B
Step-by-step explanation: Function A starts at 0,2 and function B starts at 2,2
Answer: there was 18 more before the 2:30 stop and after there was 18 less
Step-by-step explanation