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Maslowich
3 years ago
15

3-9x=6×7x(10÷5(4+3³)+2x)​

Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Answer:

871 - \sqrt(758753)) (56) (871+\sqrt(758753)) (56) decimal form: 0.00114806, -31.0829092

Step-by-step explanation:

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Form the perfect square trinomial in the process of completing the square. What is the value of c?
oksian1 [2.3K]

Answer:

The answer is 9/4

Step-by-step explanation:

8 0
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Simplify -2(4f+6)+3(4f-6)
hoa [83]
It will be 4f-30. Using substitution, you get (-8f-12) + (12f-18). Adding this together you get -8f-12+12f-18. Then you add -8f and 12f to get 4f, and add -12 and -18 to get -30. 
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Sammy has a rectangular doormat on her porch. The mat is \dfrac45\text{ m} 5 4 ​ mstart fraction, 4, divided by, 5, end fraction
Otrada [13]

Answer:

Area of the rectangular doormat = 2/5 m²

Step-by-step explanation:

Length of the rectangular doormat = 4/5m

Width of the rectangular doormat = 1/2m

What is the area of the doormat?

Area of a rectangle = length × width

= 4/5m × 1/2m

= (4×1) / (5×2)

= 4 / 10

= 2/5 m²

Area of the rectangular doormat = 2/5 m²

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3 years ago
Orlando is measuring the angles of a triangle. He measures the first two angles and gets 30° and 70°. What should be the measure
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8 0
3 years ago
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Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t
zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

<em>Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.</em>

<em>(a) How many different groups of 5 problems can be chosen from the 12</em>

<em>problems?</em>

<em>(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?</em>

<u>In (a)</u>

<u></u>

Apply the formula

\frac{n!}{(n-r)!(r!)}

where n=12 and r=5

substitute values

=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792

In (b)

If Jerry did only 5 problems of one assignment then the probability  will be

\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}

<em />

<em />

4 0
4 years ago
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