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kotykmax [81]
3 years ago
5

Jason read 70% of the 310 pages How many pages did he read

Mathematics
2 answers:
Kazeer [188]3 years ago
6 0
He read 217 pages sisklslsls
dezoksy [38]3 years ago
3 0
70% is the same as 7/10
first find 1/10 of 310 (310/10=31)
so since 31 is 1/10, you multiply by 7 to get 7/10
31×7=217
he read 217 pages
hope this helps!
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Help me please again
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x=2
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3 years ago
The typing speeds for the students in a typing class is normally distributed with mean 44 words per minute and standard deviatio
Rasek [7]

Answer:

15.87%

Step-by-step explanation:

*Probability-Below 15.87%

Z1=-1

*x-1 38

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2 years ago
This is the last question I need please help (the first one to help will be marked brainliest!)
PilotLPTM [1.2K]

Answer:

x = 19

Step-by-step explanation:

The 5x + 30 should also = 125, since they both have the same angle.

So you can make this equation:

125 = 5x + 30

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3 years ago
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A fancy rug in the shape of a trapezoid has an area of 800 square inches and the sum of the lengths of its parallel sides is 80
Artist 52 [7]

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3 years ago
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A) Construct a 95% confidence interval for the average test score for Delhi students. (1 Mark)
svetlana [45]

The solution to all the answers are given below.

The complete question includes

Grades on a standardized test are known to have a mean of 1,000 for students in the Delhi. 453

randomly selected Delhi students take the test, yielding sample mean of 1,013 and sample standard

deviation (s) of 108.

<h3>What is Confidence Interval ?</h3>

It is given by

Confidence Interval for 95% confidence Interval is given by

\rm Z = X \pm  1.96 \dfrac{\sigma}{\sqrt{n}}

(a) Construct a 95% confidence interval for the mean test score for Delhi students.

The confidence interval is given by

\rm 1,013 \pm  1.96 \dfrac{\sigma}{\sqrt{n}}

\rm 1,013 \pm  1.96 \dfrac{108}{\sqrt{453}}

1013 ± 5.07

so the interval is  [1003.06,1022.94]

(b)Yes, since the null of no difference is rejected at the 5% significance level (interval excludes Delhi sample mean of 1,013)

(c) Another 503 Delhi students are randomly selected to take a 3-hour prep course and then give the test. Their average score is 1,019 with a standard deviation of 95.

The standard deviation now is

\rm \sqrt{\dfrac{95^2}{453} + \dfrac{108^2}{503}}

= 6.61

The interval is given by

(1,019-1,013) \pm 1.96 \dfrac{\sigma}{\sqrt{n}}

= [-7,+19]

(d) No, the interval includes 0, the null difference between the two populations

To know more about Confidence Interval

brainly.com/question/24131141

#SPJ1

5 0
2 years ago
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