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Pani-rosa [81]
3 years ago
13

A motorist left Lagos at 11

Mathematics
1 answer:
Nitella [24]3 years ago
3 0
Your answer is an average of 84 mph
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At the flea market Paul found 4 buckets of LEGOs with each bucket containing 1,398 LEGO pieces. If he wanted to split the LEGO p
Hoochie [10]

1,398 * 4 = 5,592

5,592/3 = 1,864

Each pile would have 1,864 legos.

3 0
4 years ago
Read 2 more answers
What multiplied by 0.09 equals 9
Valentin [98]

Answer:

100

Step-by-step explanation:

4 0
3 years ago
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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
lutik1710 [3]
<h3>Answer: Choice C</h3>

cos(a - b) = cos(a)cos(b) + sin(a)sin(b)

In this case, we'd have a = 180 and b = q, so,

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(180 - q) = cos(180)cos(q) + sin(180)sin(q)

cos(180 - q) = -1*cos(q) + 0*sin(q)

cos(180 - q) = -cos(q) + 0

cos(180 - q) = -cos(q)

8 0
3 years ago
Pls help;)))))))))))))))(
rewona [7]

Answer:

Option 2)

Step-by-step explanation:

In a function, any number can be an x-coordinate only once.

Option 1) The 2 appears twice as x.

Option 2) All x-coordinates are different.

Option 3) The 2 appears twice as an x-coordinate.

Option 4) The 3 appears twice as an x-coordinate.

Answer: Option 2)

4 0
4 years ago
A password is to be made from a string of five characters chosen from the lowercase letters of the alphabet and the numbers 0 th
alex41 [277]

Using the Fundamental Counting Theorem, it is found that for each case, the total number of outcomes is:

a) 60,466,176.

b) 5,961,600.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

Item a:

No restrictions, hence for each of the five characters, there are 36 outcomes, hence n_1 = \cdots = n_5 = 36.

Then, the possible number of passwords is:

N = 36^5 = 60466176

Item b:

The letters and the digits have to be alternated, hence:

  • Starting with a letter, n_1 = n_3 = n_5 = 36, n_2 = n_4 = 10.
  • Starting with a digit, n_1 = n_3 = n_5 = 10, n_2 = n_4 = 36.

Then, the possible number of passwords is:

N = 36^3 \times 10^2 + 10^3 \times 36^2 = 5961600

To learn more about the Fundamental Counting Theorem, you can take a look at brainly.com/question/24314866

5 0
3 years ago
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