Given:
A figure of two congruent triangles.
To find:
The triangle congruence postulate by which the given triangles are congruent.
Solution:
First label the vertices as shown below.
In triangle ABC and triangle CDA,
(Given)
(Given)
(Common side)
The corresponding two sides and their included angle are congruent in both triangles. So, triangles are congruent by SAS congruence postulate.
[SAS congruence postulate]
Therefore, the correct option is B.
Answer:
One Solution
Step-by-step explanation:
That's My Answer :)
First of all, let's recall the area of a triangle, knowing its base (b) and height (h):
The exercise is showing you that, if you inscribe a polynomial with more and more side, the area of the polynomial will approximate the area of the circle better and better (you can see youself that the polygon is "filling" the circle more and more as the number of sides increase).
Now, the second column tells you the area of each of the triangles the polygon is split into. So, we can see that the first polygon is split into 3 triangles, each of them having base 1.73 and height 0.5.
So, the area of each triangle is
There are three of these triangles, so the area of the whole polygon is
In the second case, you have six triangles, each with base 1 and height 0.87. So, the whole area is
Finally, in the last case you have 8 triangles, each with base 0.77 and height 0.92. So, the whole area is
