Question

Two parallel lines are crossed by a transversal.what is the value of x ?

Answer 1

Answer:

The value of x= 12.

Step-by-step explanation:

Given two parallel lines b nd c are crossed by a transversal  line 'a'.

$y+ 115^{\circ}=180^{\circ}$

By linear sum property

$y=180-115$

By subtraction property of equality

We get y= $65^{\circ}$

By simplification

$5x+5=65^{\circ}$

b and c are parallel lines and cut by transversal line a then alternate interior angles are equal.

$5x=65-5$

By subtraction property of equality

5x=60

$x=\frac{60}{5}$

By division property

x=12

Hence, the value of xis 12.

Answer 2

Answer:

12

Step-by-step explanation:

(5x+5)+(115)=180

180-120=60

60/5=12