A time of 40.7 minutes is taken for 170 grams of element X to decay to 5 grams.
<h3>How to analyze a radioactive decay case</h3>
Let suppose that element X experiments a <em>simple radioactive</em> decay, that is, that the element X becomes gradually into another less radioactive stable element in time.
We know that decay behaves exponentially and follows this model:
(1)
Where:
- - Initial mass, in grams
- <em>t</em> - Time, in minutes
- <em>τ</em> - Time constant, in minutes
- <em>m(t)</em> - Current mass, in grams
The time constant can be described in terms of half-life (), in minutes, through the following expression:
(2)
If we know that , and , then the time needed for the decay is:
<em>τ ≈ 11.541 min</em>
<em>t ≈ 40.698 min</em>
A time of 40.7 minutes is taken for 170 grams of element X to decay to 5 grams.
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- Domain:<u> List of x-values that are possible on a line</u>
- Range: <u>List of y-values that are possible on a line</u>
- Interval Notation: <u>Notation that represents the interval using the endpoints.</u> Brackets mean that the endpoint is included, parentheses means that it isn't. (e.g: (20,27] . 20 isn't included in the interval, 27 is.)
- Additional Note: <u>Open circles mean that the point is excluded, closed circles mean that the point is included.</u>
Firstly, let's look at the domain. We see an open circle at x = -6 and a closed circle at x = -1, then an open circle at x = 1 and a closed circle at x = 5. Using what we know, this means that <u>the domain is </u>
Next, let's look at the range. We see an open circle at y = -3 and a closed circle at y = 2, then we see a closed circle at y = 3 and an open circle at y = 7. Using what we know, this means that <u>the range is </u>
Answer:
Yes it is
Step-by-step explanation:
Answer:
<em><u>note:</u></em>
<em><u>find the attached solution</u></em>
Answer:
7. 0.7 C is colder
b.-0.7 is warmer
Step-by-step explanation: