Answer:
115
Step-by-step explanation:
set up the equation to find x:
GFN+NFG=GFE
(4x+10)+(14x+3)=157
calculate for x
you'll get x=8
put 8 into NFE
14(8)+3=115
Given:
P: (2,0,5)
L: (0,6,4)+t(7,-1,5)
and required plane, Π , passes through P and perpendicular to L.
The direction vector of L is V=<7,-1,5>.
For Π to be perpendicular to V, Π has V as the normal vector.
The equation of a plane with normal vector <7,-1,5> passing through a given point P(xp,yp,zp) is
7(x-xp)-1(y-yp)+5(z-zp)=0
Thus the equation of plane Π passing through P(2,0,5) is
7(x-2)-y+5(z-5)=0
or alternatively,
7x-y+5z = 14+25
7x-y+5z = 39
4 is 101 and 1 and 3 are 129
Answer:
∠FJH ≅ ∠BJA
Step-by-step explanation:
From the given image, we notice that the only congruent relation ∠FJH has is with ∠BJA.
Where ∠BJA is vertically opposite to ∠FJH
Hence, we can say that ∠FJH ≅ ∠BJA since both these angles are vertically opposite
Answer:
36 or 2
Step-by-step explanation:
Its one of those two its not negative.