3 years ago

A. The area of a circle is 113.1 ft to the 2nd power. What would the diameter have to be.

Mathematics

1 answer:

irina [24]3 years ago

3 0

What are the answers

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Answer:

$\dfrac{c^{10}}{d^{10}}$

Step-by-step explanation:

Although the way you wrote problem, this is not what it looks like, I think this is what you meant.

$\dfrac{c^{-6} \times d^{4}}{c^{-16} \times d^{14}} =$

$= \dfrac{c^{-6}}{c^{-16}} \times \dfrac{d^{4}}{d^{14}}$

$= c^{-6 - (-16)} \times d^{4 - 14}$

$= c^{-6 + 16} \times d^{-10}$

$= c^{10} \times d^{-10}$

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