This is the number of combinations of 2 from 23
23C2 = 23! / 2! 21!
A quick way to do this is 23*22 / 2 = 253
300x .02= 6
6x10=60
Therefore the answer is $360
Answer:
3.7
Step-by-step explanation:
2r(pi)(∅/360)
2*3*(pi)*(70/360)
6*(pi)*(0.19444...)
3.665191429188092
3.7
Answer:
2-sqrt14/2, 2+sqrt13/2.
Step-by-step explanation:
What you do is you have to do the quadratic equation like it says in the problem.
x= −b± sqrtb^2 −4ac
/2a
.
a=-2, b=4, c=5.
x=-4±sqrt(4)^2-4(-2)(5)/2(-2).
x=-4±sqrt16+40/-4.
x=-4±2sqrt14/-2.
2-sqrt14/2, 2+sqrt13/2. is your answer once you have done everything.
