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3 years ago

HELP AND WHO WANTS TO CHAT

Mathematics

2 answers:

netineya [11]3 years ago

7 0

Answer:

less than half

Step-by-step explanation:

elena-14-01-66 [18.8K]3 years ago

6 0

Answer:

Less than half.

Step-by-step explanation:

Half is 50%. 13% is less than 50%, so 13% is less than half. Also, for the next questions you have, any percent above 50% will be more than half, while any percent less than 50% will be less than half.

Hope this helps! Have a nice day c:

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In Exercise, use the properties of exponents to simplify the expression.<br> 32(3- 2)

zavuch27 [327]

Answer:

Step-by-step explanation:

We have given expression $3^2\times 3^{-2}$

We have to simplify the expression with use of property of exponent

According to property of exponent when two functions are multiplied with each other having exponent then their exponent are added to each other

So $3^2\times 3^{-2}=3^{2-2}=3^0$

Now according to exponent property if 0 is the exponent of any number then its result will be 1

So $3^0=1$

4 0

3 years ago

What are the roots of the polynomial equation x2 + x- 72 =0

Alex17521 [72]

First, you can factor them into (x-8)(x+9)=0 then set x-8=0 and x+9=0, in which you get X = 8 or X = -9

5 0

3 years ago

The spokes of a bicycle wheel form 10 congruent central angles. The diameter of the circle formed by the outer edge of the wheel

N76 [4]

find the circumference and divide it by 10

$c = d\pi \\ c = 18\pi \\ c = 56.548668... \\ \\ arc = \frac{c}{10} \\ arc = 5.654867... \\ arc = 5.7$

4 0

3 years ago

Which statement about the ordered pairs (–2, 9), (0, 9) and (3, 9) is not true?

Lelu [443]

Answer:

The slope of these coordinates is 0.

It is a horizontal line.

Step-by-step explanation:

8 0

3 years ago

We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando

coldgirl [10]

Answer: $(9.27025,\ 11.12975)$

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : $\overline{x}=10.2$

sample standard deviation : $s= 1.5$

Significance level ; $\alpha= 1-0.90=0.10$

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = $t_{\alpha/2, df}=t_{0.05 , 8}=1.8595$

Confidence interval for the population mean :

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

90% confidence interval for the mean value will be :

$10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}$

$10.2\pm (1.8595)\dfrac{1.5}{3}$

$10.2\pm (1.8595)(0.5)$

$10.2\pm (0.92975)$

$(10.2-0.92975,\ 10.2+0.92975)$

$(9.27025,\ 11.12975)$

Hence, the 90% confidence interval for the mean value= $(9.27025,\ 11.12975)$

6 0

3 years ago