A = lw
44 = 3 2/3 w
w = 44 / (3 2/3)
w = 12
The area is 336 is you multiply the outer numbers then subtract the numbers on the in side that's what you get
If it’s not graded does it really matter but it’s 4042 I think
Answer:
The probability that X is between 1.48 and 15.56 is 
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
X is a normally distributed random variable with a mean of 8 and a standard deviation of 4.
This means that 
The probability that X is between 1.48 and 15.56
This is the pvalue of Z when X = 15.56 subtracted by the pvalue of Z when X = 1.48. So
X = 15.56



has a pvalue of 0.9706
X = 1.48



has a pvalue of 0.0516
0.9706 - 0.0516 = 0.919
Write out the probability notation for this question.

The probability that X is between 1.48 and 15.56 is 
Answer:
There are 260 seats in economy class and 100 seats in business class
Step-by-step explanation:
To solve this problem we first have to calculate the fraction of economic and business seats with respect to the total
We are told that every 13 seats in economy class there are 5 seats in business class
13 + 5 = 18
This means that if there are 18 seats 13 will be economic and 5 business
economic seats = 13/18
business seats = 5/18
To find out the number of seats in the airplane of each class, we have to multiply the total number of seats by these fractions
economic seats = 360 * 13/18
economic seats = 260
business seats = 360 * 5/18
business seats = 100