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3 years ago

I am building a fence in my backyard. I have 120 nails, and I need to put 4 nails

2 answers:

8 0

120/4 is 30
You'll be able to put 4 nails thirty times.
You put them every 6 feet
So, you have 5 feet before running out.

Mama L [17]3 years ago

4 0

5 feet because 120 divided by 4 is 30

You might be interested in

Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5

kobusy [5.1K]

Answer:

max{x²-4x²+5} = 5 at x = 0

Step-by-step explanation:

1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.

$f'(x)=0$

We get:

$f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0$

So the critical number is x = 0.

2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:

$f'(x)$ is positive when the x < 0 (for example: -6*(-1)=+)

$f'(x)$ is negative when the x > 0 (for example: -6*(1)=-)

Therefore, you have a local maximum.

Now just get the Y value by plugging in the critical number in the original function. $f(0)=5$

local maximum is (0,5)

4 0

1 year ago

A larger number is one less than five times a smaller number. The sum of

Andre45 [30]

Answer:

whichever of these formats you need its the same answer (16/6) or 2.66666 or (2 and 2/3rds)

Step-by-step explanation:

replace smaller variable with x for example

(x) + (5x-1) = 17

6x-1=17

6x=16

x=(16/6 or 2.666666 or 2and2/3)

6 0

3 years ago

3. Write an equation in point-slope form for the line through the given point with the given slope.

ASHA 777 [7]

3C
4C
5B (parallel means same slope)

7 0

2 years ago

The ratio of boys and girls in a swim club was 2:4 there were 14 girls how many total members were there in the club

Oxana [17]

I think its 21 but im not to sure

3 0

3 years ago

A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the

Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

$P(A) = 0.90*0.03 + 0.1*0.97 = 0.124$

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

$P(A \cap B) = 0.9*0.03 = 0.027$

What is the conditional probability that she does, in fact, have the disease

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177$

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0

3 years ago