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3 years ago

I am building a fence in my backyard. I have 120 nails, and I need to put 4 nails

2 answers:

8 0

120/4 is 30
You'll be able to put 4 nails thirty times.
You put them every 6 feet
So, you have 5 feet before running out.

Mama L [17]3 years ago

4 0

5 feet because 120 divided by 4 is 30

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How should the decimal point in 52.48 be moved to determine the product 52.48×105 ?

tensa zangetsu [6.8K]

Answer:

5510.4

Step-by-step explanation:

4 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.

schepotkina [342]

Answer:

Step-by-step explanation:

The given equation of line is

$3x+6y=-18$

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

$3x+6y+18=0$ ...(i)

If a line is defined as $ax+bx+c=0$ , then the slope of the line is

$m=-\dfrac{a}{b}$

In equation (i), a=3, b=6 and c=18. So, slope of the line is

$m_1=-\dfrac{3}{6}=-\dfrac{1}{2}$

Let $m_2$ be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

$m_1\cdot m_2=-1$

$(-\dfrac{1}{2})\cdot m_2=-1$

Multiply both sides by -2.

$m_2=2$

Therefore, the slope of perpendicular line is 2.

6 0

3 years ago

Can someone help please?

Over [174]

Answer:

its A

Step-by-step explanation:

8 0

3 years ago

A sphere has a radius of 4 in. Which equation finds the volume of the sphere?

Ede4ka [16]

Volume : 4πR³/3

R=4

↓

V = 4π·4³/3 or $\frac{4}{3}*\pi *(4)^{3}$

5 0

4 years ago

Read 2 more answers

PLSS HELP ILL GIVE YOU BRAINLIEST!!

uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

$(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20} \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}$

Q2)

Apply phythogoras theorem:

$CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4$

Q3)

Apply phythogoras theorem again:

$BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218} \\\\BC=\sqrt{218} \\\\BC=14.76$

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

4 0

3 years ago