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3 years ago

Help, please :) appreciate it

Mathematics

1 answer:

myrzilka [38]3 years ago

6 0

27). 8a+7

28). 10k-1

29). 2n-48

30). x+16

31). 14b+3c-3

32) -2y=10

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I need help with coming up with equation

Natali5045456 [20]

Let's call a child's ticket $c$ and an adult's ticket $a$ . From this, we can say:

$c + a = 116$ ,

since 116 tickets are sold in total.

Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

$\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750$ .

Given these values, we can say:

$17000a + 12750c = 1653250$ ,

since each adult ticket $a$ costs 17,000 and each child's ticket $c$ costs 12,750, and these costs sum to 1,653,250.

Now, we have two equations:

$17000a + 12750c = 1653250$

$c + a = 116$

Let's solve:

$17000a + 12750c = 1653250$

$a = 116 - c$

Find $a$ on its own, which will allow us to substitute it into the first equation

$17000(116 - c) + 12750a = 1653250$

Substitute in $116 - c$ for $a$

$1972000 - 17000c + 12750c = 1653250$

Apply the Distributive Property

$1972000 - 4250c = 1653250$

Combine like terms

$4250c = 318750$

Subtract 1972000 from both sides of the equation and multiply both sides by -1

$c = 75$

We have now found that 75 child's tickets were sold. Thus,

$75 + a = 116 \Rightarrow a = 116 - 75 = 41$ ,

41 adult tickets were sold as well.

In sum, 41 adult tickets were sold along with 75 child tickets.

6 0

3 years ago

ILL BRAINLIEST YOU PLEASE HELP ME

-Dominant- [34]

Answer:

x = 7/ $\sqrt{2}$ or 4.949747468

Step-by-step explanation:

45-45-90 triangles have a specific pattern.

The smaller sides are x, & the hypotenuse is $x*\sqrt{2}$

With this knowledge, we know we have to divide the hypotenuse by $\sqrt{2}$ to get the smaller sides, so we divide 7 by the $\sqrt{2}$ to find x.

4 0

3 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

4 years ago

4e^2x-6=10<img src="https://tex.z-dn.net/?f=4e%5E2x-6%3D10" id="TexFormula1" title="4e^2x-6=10" alt="4e^2x-6=10" align="absmiddl

Taya2010 [7]

X=4/e^2 or X=0.541341

3 0

3 years ago

Read 2 more answers

Can someone help w number 4

strojnjashka [21]

Answer:

angle DFG = 49 degrees

angle JKL = 41 degrees

Step-by-step explanation:

When angles are complementary with each other, it means that if you add both of the angles up, it adds up to 90 degrees.

In this question, you would have to add up angle DFG and angle JKL and find the x that makes the equation equal to 90 degrees.

angle DFG = x + 5

angle JKL = x - 3

(x + 5) + (x - 3) = 90

2x + 2 = 90

2x = 90 - 2

2x = 88

x = 44

But since we have to find out the angle measures, we have to the "x = 44" with the x's in the DFG and JKL angles.

DFG = (44) + 5 = 49

JKL = (44) - 3 = 41

7 0

3 years ago