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Brilliant_brown [7]
2 years ago
11

Please help me with my math problems

Mathematics
2 answers:
Alika [10]2 years ago
8 0

Answer:

Pic 1:

A = A

B = B

C = A

Pic 2:

A = B

B = A

C = B

D = A

natulia [17]2 years ago
7 0

Answer:

is it subtraction or addition?

Step-by-step explanation:

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PLEASE HELP GEOMETRY PLEASE! SHOW WORK!!
MissTica

Answer:

area = 24 cm²

Step-by-step explanation:

area = 1/2 x 6 x 8 = 24 cm²

7 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
How many centimeters are in 10 feet given that 1 inch = 2.54 cm
lions [1.4K]
304.8 centimeters is the answer to this question.

7 0
3 years ago
What is the area of this composite figure? <br> A . 12ft²<br> B. 80ft²<br> C. 88ft²<br> D. 100ft²
Eva8 [605]

Answer:

c.)88^2

Step-by-step explanation

4 0
3 years ago
Wich is equivalent to sqrt10^3/4 x
Sergio039 [100]

Answer:

( \sqrt[4]{10} ) ^{3x}

7 0
3 years ago
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