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saul85 [17]
3 years ago
7

Divide 33 photoes into 2 groups so the ratio is 4 to 7

Mathematics
2 answers:
Kryger [21]3 years ago
4 0
Add 4 and 7 =11

group 1= 4/11×33=12 potatoes

group 2 =7/11*33= 21 potatoes
natali 33 [55]3 years ago
3 0

Answer:

12:21

Step-by-step explanation:

4 + 7 = 11

33/11 = 3

3x4=12 & 3x7=21

Therefore, ratio is, 12:21

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Answer:

a= 2/b-c

Step-by-step explanation:

We want isolate for a or to be itself

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factor out a

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5 0
3 years ago
The sum of the diagonals of a rhombus is 5√2.
Alex
Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
= \frac{1}{2} BD (AO + OC)
\frac{1}{2} BD \times AC

So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
BD \times AC = 8
Now, AC + \: BD = 5 \sqrt{2}

Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
AC {}^{2} + BD {}^{2} + 2 \times 8 = 50
AC {}^{2} + BD {}^{2} = 50 - 16
AC {}^{2} + BD {}^{2} = 34

In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
AC {}^{2} + BD {}^{2} = 4 AB {}^{2}
34 = 4 AB {}^{2}

Square rooting both sides
\sqrt{34} = 2 AB
Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units.

Hope it helps!

7 0
3 years ago
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Phantasy [73]
3 by 2 by 4
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4 by 5 by 5
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4 0
3 years ago
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