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4 years ago

Which equation is equivalent to x2+10x+2=0 ?

Mathematics

1 answer:

Svet_ta [14]4 years ago

4 0

x =(10-√92)/2=5-√ 23 = 0.204 or x =(10+√92)/2=5+√ 23 = 9.796

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If pens cost 15 cents, how many can you buy with $3.00?

aliina [53]

3.00/0.15 = 20
You can buy 20 pens

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3 years ago

Read 2 more answers

What is the solution to the equation 3.6m-2.7=-1.8m

Liula [17]

Answer:

m = 1.5

Step-by-step explanation:

hope this helped

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4 years ago

Make sure the answer is 100% correct. Then circle the answer in a circle.

Vladimir [108]

Answer:
False
Any integers that the numbers 5, 10 , 15 but 20 can be used as a counter argument against the statement.

Step-by-step explanation:

The claim is that A⊆B which stands for that A is a SUBSET in B, or that B contains A.

The truth is that B⊆A since 5 has more possible outcomes than 20 in the number of integers.
So the list of all possible answers are r5, r10, and r15 where N⊆Z.

For example I choose r=3 and r15, 3(15)= 45. I can use the number 45 as a counter argument that the statement of A⊆B is false.

6 0

2 years ago

Radioactive Decay

SpyIntel [72]

Answer:

Percentage of (226Ra) after 900 years is 68%

Step-by-step explanation:

Let P(t) be the amount of (226Ra) present at any time t

Half life of (226 Ra) = 1599 years

If P₀ is initial amount of (226 Ra) then after 1599 years

P(1599)=P₀/2

Decay i amount of radioactive substance is related to time t as

$\frac{dP}{dt}=kP(t)\\\\\frac{1}{P}\,dP=kdt\\\\Integrating\,\, both\,\,sides\\\\ln|P|=kt+c\\\\P(t)=Ce^{kt}\\\\at \,\, t=0\,\, P(0)=P_{o}\\\\P(0)=Ce^{k0}\\\\P_{o}=C\\\\then\\\\P(t)=P_{o}e^{kt}$

To find value of k

$at\,\, t=1599\,years\\\\P(1599)=\frac{P_{o}}{2}\\\\then\\\\\frac{P_{o}}{2} =P_{o}e^{k(1599)}\\\\\frac{1}{2} =e^{k(1599)}\\\\ln|\frac{1}{2}|=k(1599)\\\\k=\frac{ln|\frac{1}{2}|}{1599}=-4.3\times 10^{-3}\\\\\implies P(t)=P_{o}e^{-4.3\times 10^{-3}t}\\\\at\,\, t=900 \\\\P(900)=P_{o}e^{-4.3\times 10^{-3}(900)}\\\\P(900)=0.68P_{o}$

Percentage of radioactive element is:

Amount after 900 years $=\frac{P(900)}{P_{o}}\times 100\\\\=\frac{0.68P_{o}}{P_{o}}\times 100\%\\\\=68\%$

3 0

3 years ago

Which image shows a reflection of Polygon P using line e? Select the correct choice.

densk [106]

Answer:

Step-by-step explanation:

Because the point on the top on the original would still be on top so it is 100% B

Hope This Helped

5 0

2 years ago